56x^2+450x+67=0

Solution for 56x^2+450x+67=0 equation:

56x^2+450x+67=0

a = 56; b = 450; c = +67;
Δ = b2-4ac
Δ = 4502-4·56·67
Δ = 187492
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{187492}=\sqrt{4*46873}=\sqrt{4}*\sqrt{46873}=2\sqrt{46873}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(450)-2\sqrt{46873}}{2*56}=\frac{-450-2\sqrt{46873}}{112}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(450)+2\sqrt{46873}}{2*56}=\frac{-450+2\sqrt{46873}}{112}
$